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Teacher sheet · Ages 15–16 · about 45–50 minutes

Energy: calculations, conservation and efficiency

Lesson page: echoesof.science/school/energy/ages-15-16/ · Pupil worksheet: echoesof.science/school/energy/ages-15-16/print/

Learning aims

Lesson plan

TimeActivity
5 minStarter: why does a bouncing ball eventually stop?
10 minRead the text; work through the falling-rock example.
25 minBouncing-ball efficiency experiment with video.
5 minCompare balls; discuss the uncertainty of video readings.
5 minQuiz, or the game as homework.

Materials for the experiment

Safety: Drop the balls, don't throw them. Keep the area clear and don't stand on tables or chairs to drop from higher than you can reach safely.

Common misconceptions

Pupils may think…Actually…
Energy is lost when a ball stops bouncing.It is not destroyed: it is dissipated as thermal energy (and sound).
Efficiency can be more than 100% if a machine is very good.Useful output can never exceed the input, because total energy is conserved.
A higher power means more energy.Power is energy per second; total energy also depends on the time.

Worksheet answers

  1. Bars: E_p at the top; E_k (nearly the same) just before impact; a smaller E_p at the top of the bounce; the difference is dissipated as heat and sound.
  2. E_p = 0.060 × 9.8 × 1.5 ≈ 0.88 J. ½mv² = mgh gives v = √(2gh) = √(2 × 9.8 × 1.5) ≈ 5.4 m/s.
  3. Efficiency = 0.62 ÷ 1.00 = 0.62 = 62%. The other 38% is dissipated mainly as thermal energy in the ball and floor, and as sound.
  4. Saving = (60 − 9) W × 1000 h = 51 000 Wh = 51 kWh.

Quiz answers

  1. What is the kinetic energy of a 2 kg ball moving at 3 m/s? 9 J. E_k = ½ × 2 × 3² = 9 J.[3]
  2. How much potential energy does a 5 kg box gain when lifted 2 m? (g = 9.8 m/s²) 98 J. E_p = m·g·h = 5 × 9.8 × 2 = 98 J.[3]
  3. A 10 kg rock falls 10 m from rest. Ignoring air resistance, its kinetic energy is then… 980 J. The 980 J of lost potential energy becomes kinetic energy.[3]
  4. A 60 W bulb produces 5 W of light. Its efficiency is about… 8%. Efficiency = 5 ÷ 60 ≈ 0.08 = 8%.[5]
  5. A 0.200 kW computer runs 6 hours a day for 30 days. How much energy does it use? 36 kWh. 0.200 kW × 180 h = 36 kWh.[5]
  6. Which has the highest typical efficiency? An electric motor. Representative values: electric motor 98%, petrol engine 30%, solar cell 10%.[4]

Going further

Plot h₂ against h₁ for each ball. Is the graph a straight line through the origin? What would a constant efficiency look like on this graph? Research why a power station's efficiency is limited.

Sources used in this lesson

Full list with links and a note on each source's reliability: echoesof.science/school/energy/sources/

Privacy: the lesson pages have no ads, no tracking and no cookies. Quiz answers and game scores stay in the pupil's browser. A short video for each age is coming.

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